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= \frac{1}{2} \times 15 \times h \implies h = \frac{84 \times 2}{15} = \frac{168}{15} = 11.2 \text{ سم}

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إذن، طول أقصر ارتفاع هو \(\boxed{11.2 \text{ سم}}\).

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الحل: لحساب \(\tan 75^\circ\)، نستخدم صيغة جمع الزوايا للدالة الظل:

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\tan(\alpha + \beta) = \frac{\tan \alpha + \tan \beta}{1 - \tan \alpha \tan \beta}

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نعبر عن \(75^\circ\) كمجموع \(45^\circ + 30^\circ\):

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\tan 75^\circ = \tan(45^\circ + 30^\circ) = \frac{\tan 45^\circ + \tan 30^\circ}{1 - \tan 45^\circ \tan 30^\circ}

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